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Mathematics
x 2 15 x = 50 x^(2)-15 x=-50
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To solve this equation, we can start by rearranging it so that one side is equal to zero:
x 2 15 x + 50 = 0 x^(2)-15 x+50=0
Now we can factor the left-hand side of the equation:
( x 5 ) ( x 10 ) = 0 (x-5)(x-10)=0
Using the zero product property, we know that either x 5 = 0 x-5=0 or x 10 = 0 x-10=0:
x 5 = 0 or x 10 = 0 x-5=0quad"or"quad x-10=0
Solving for x x in each case, we get:
x = 5 or x = 10 x=5quad"or"quad x=10
Therefore, the solutions to the original equation are x = 5 x=5 and x = 10 x=10.
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