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Physics
A capacitor with a capacitance of 2.00 μ F 2.00 mu F is connected to a 12.0 V 12.0 V battery. What is the amount of charge on each plate of the capacitor?
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To find the charge on each plate of the capacitor, we can use the formula Q = C V Q=CV, where Q Q is the charge, C C is the capacitance, and V V is the voltage across the capacitor. By substituting the given values, we get Q = 2.00 μ F × 12.0 V = 24 μ C Q=2.00 mu F xx12.0 V=24 mu C. Therefore, the magnitude of the charge on each plate of the capacitor is 24 microcoulombs.
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