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Physics
How many grams of Li3N can be formed from 1.75 moles of Li? Assume an excess of nitrogen. 6 Li(s) + N2(
g. → 2 Li3N(s)
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The balance chemical reaction is:

6 Li(s) + N2(g) → 2 Li3N(s)

We use the amount of the Lithium reactant and the relations of the substances from the reaction to calculate the amount of product produced. We do as follows:

1.75 mol Li ( 2 mol Li3N / 6 mol Li ) (34.83 g / mol) = 20.32 g Li
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