Question

Chemistry

What is the mass of 1.450 mol Cd3N2?

124,2 g

234.7 g

529.6 g

738.9 g

124,2 g

234.7 g

529.6 g

738.9 g

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Best Answer

**Answer:**

529.6 g Cd₃N₂

**General Formulas and Concepts:**

**Math**

__Pre-Algebra__

Order of Operations: **BPEMDAS
**

- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction

- Left to Right

__Chemistry__

__Atomic Structure__

- Reading a Periodic Table
- Using Dimensional Analysis

**Explanation:**

__Step 1: Define__

1.450 mol Cd₃N₂

__Step 2: Identify Conversions__

Molar Mass of Cd - 112.41 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of Cd₃N₂ - 3(112.41) + 2(14.01) = 365.25 g/mol

__Step 3: Convert__

__[tex]\displaystyle 1.450 \ mol \ Cd_3N_2(\frac{365.25 \ g \ Cd_3N_2}{1 \ mol \ Cd_3N_2} ) = 529.613 \ g \ Cd_3N_2[/tex]__

__Step 4: Check__

*Follow sig fig rules and round. We are given 4 sig figs.*

529.613 g Cd₃N₂ ≈ 529.6 g Cd₃N₂