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Question
Chemistry
What is the mass of 1.450 mol Cd3N2?
124,2 g
234.7 g
529.6 g
738.9 g
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Best Answer

Answer:

529.6 g Cd₃N₂

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

Step 1: Define

1.450 mol Cd₃N₂

Step 2: Identify Conversions

Molar Mass of Cd - 112.41 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of Cd₃N₂ - 3(112.41) + 2(14.01) = 365.25 g/mol

Step 3: Convert

[tex]\displaystyle 1.450 \ mol \ Cd_3N_2(\frac{365.25 \ g \ Cd_3N_2}{1 \ mol \ Cd_3N_2} ) = 529.613 \ g \ Cd_3N_2[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 4 sig figs.

529.613 g Cd₃N₂ ≈ 529.6 g Cd₃N₂

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