Question
Physics
An asteroid is moving along a straight line. A force acts along the displacement of the asteroid and slows it down. The asteroid has a mass of 4.3 × 104 kg, and the force causes its speed to change from 7600 to 5000 m/s. (a) What is the work done by the force? (b) If the asteroid slows down over a distance of 1.4 × 106 m determine the magnitude of the force.

I have part A, just need part B
A= -7.048E11 J
Solve problem with AI

a)

$$- 7.04\times10^{11} J$$

b)

$$5.03\times10^{5} N$$

Explanation:

a)

$$m$$ = mass of the asteroid = 43000 kg

$$v_{o}$$ = initial speed of asteroid = 7600 m/s

$$v$$ = final speed of asteroid = 5000 m/s

$$W$$ = Work done by the force on asteroid

Using work-change in kinetic energy theorem

$$W = (0.5) m (v^{2} - v_{o}^{2})\W = (0.5) (43000) (5000^{2} - 7600^{2})\W = - 7.04\times10^{11} J$$

b)

$$F$$ = magnitude of force on asteroid

$$d$$ = distance traveled by asteroid while it slows down = 1.4 x 10⁶ m

Work done by the force on the asteroid to slow it down is given as

$$W = - F d\- 7.04\times10^{11} = - F (1.4\times10^{6})\F = 5.03\times10^{5} N$$

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