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In an RLC parallel circuit, the resistor has a voltage of 12 V and a current flow of 40 amperes. What is the voltage drop across the capacitor (E_C)?
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To find the voltage drop across the capacitor (E_C) in an RLC parallel circuit, we first calculate the voltage across the resistor (E_R) using the formula E_R = I * R, where I is the current flow and R is the resistance. In this case, E_R = 12 * 40 = 480 V. In a parallel circuit, the voltage drop across each component is equal, so the voltage drop across the capacitor (E_C) is also 480 V.
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