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Mathematics
Write the first four terms of the sequence with the given rule.
  1. a n = 2 n + 3 a_(n)=2n+3
  2. a n = 3 n 7 a_(n)=3n-7
  3. a n = 5 n + 6 a_(n)=5n+6
  4. a n = 4 n + 5 a_(n)=4n+5
  5. a n = 2 ( n + 3 ) a_(n)=2(n+3)
  6. a n = n 2 a_(n)=sqrt(n^(2))
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  1. a 1 = 2 ( 1 ) + 3 = 5 , a 2 = 2 ( 2 ) + 3 = 7 , a 3 = 2 ( 3 ) + 3 = 9 , a 4 = 2 ( 4 ) + 3 = 11 a_(1)=2(1)+3=5,a_(2)=2(2)+3=7,a_(3)=2(3)+3=9,a_(4)=2(4)+3=11
    The first four terms are 5 , 7 , 9 , 11 5,7,9,11.
  2. a 1 = 3 ( 1 ) 7 = 4 , a 2 = 3 ( 2 ) 7 = 1 , a 3 = 3 ( 3 ) 7 = 2 , a 4 = 3 ( 4 ) 7 = 5 a_(1)=3(1)-7=-4,a_(2)=3(2)-7=-1,a_(3)=3(3)-7=2,a_(4)=3(4)-7=5
    The first four terms are 4 , 1 , 2 , 5 -4,-1,2,5.
  3. a 1 = 5 ( 1 ) + 6 = 11 , a 2 = 5 ( 2 ) + 6 = 16 , a 3 = 5 ( 3 ) + 6 = 21 , a 4 = 5 ( 4 ) + 6 = 26 a_(1)=5(1)+6=11,a_(2)=5(2)+6=16,a_(3)=5(3)+6=21,a_(4)=5(4)+6=26
    The first four terms are 11 , 16 , 21 , 26 11,16,21,26.
  4. a 1 = 4 ( 1 ) + 5 = 9 , a 2 = 4 ( 2 ) + 5 = 13 , a 3 = 4 ( 3 ) + 5 = 17 , a 4 = 4 ( 4 ) + 5 = 21 a_(1)=4(1)+5=9,a_(2)=4(2)+5=13,a_(3)=4(3)+5=17,a_(4)=4(4)+5=21
    The first four terms are 9 , 13 , 17 , 21 9,13,17,21.
  5. a 1 = 2 ( 1 + 3 ) = 8 , a 2 = 2 ( 2 + 3 ) = 10 , a 3 = 2 ( 3 + 3 ) = 12 , a 4 = 2 ( 4 + 3 ) = 14 a_(1)=2(1+3)=8,a_(2)=2(2+3)=10,a_(3)=2(3+3)=12,a_(4)=2(4+3)=14
    The first four terms are 8 , 10 , 12 , 14 8,10,12,14.
  6. a 1 = 1 2 = 1 , a 2 = 2 2 = 2 , a 3 = 3 2 = 3 , a 4 = 4 2 = 4 a_(1)=sqrt(1^(2))=1,a_(2)=sqrt(2^(2))=2,a_(3)=sqrt(3^(2))=3,a_(4)=sqrt(4^(2))=4
    The first four terms are 1 , 2 , 3 , 4 1,2,3,4.
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