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Mathematics
d = 137 17 = 120 , m 15 sing term , 137 d=137-17=120,(longrightarrow)/(m 15 sing " term "),137,
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It seems like there is a typo in the question. However, based on the given information, the common difference is correctly computed as d = 137 17 = 120 d=137-17=120, where 137 137 is the next term and 17 17 is a previous term.
To find the 15th term in this arithmetic sequence, we need to use the formula:
a n = a 1 + ( n 1 ) d a_(n)=a_(1)+(n-1)d
where a n a_(n) is the n nth term, a 1 a_(1) is the first term, d d is the common difference, and n n is the number of terms.
We can plug in the given information to find the first term a 1 a_(1):
17 = a 1 + ( 1 1 ) 120 17=a_(1)+(1-1)120
Simplifying, we get:
17 = a 1 17=a_(1)
Now, we can use the formula to find the 15th term, where n = 15 n=15:
a 15 = 17 + ( 15 1 ) 120 a_(15)=17+(15-1)120
Simplifying, we get:
a 15 = 17 + 14 ( 120 ) a_(15)=17+14(120)
a 15 = 1697 a_(15)=1697
Therefore, the 15th term in this arithmetic sequence is 1697 1697.
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